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geek tragedy

(68,868 posts)
30. I get that you recognize the reality of the situation.
Thu Apr 21, 2016, 04:10 PM
Apr 2016

I think others are actually buying the idea that it's a jumpball if Clinton doesn't hit 2383 pledged.

To me it's inconceivable Sanders would contest it if Clinton hits 2026 pledged.

I think Clinton will hold off declaring victory until she hits that number. She could declare earlier based on superdelegates if things go as expected, but that would be a bad idea.

You are correct... pkdu Apr 2016 #1
No, you're not correct... SidDithers Apr 2016 #2
You are incorrect. You make some assumptions which are not certain. morningfog Apr 2016 #6
And superdelegates will do nothing more than be a rubber stamp... SidDithers Apr 2016 #14
Barring something earth shattering, yes. Supers are either irrelevant or undemocratic and should morningfog Apr 2016 #32
The supers vote with their states Stuckinthebush Apr 2016 #16
Best line ever! northernsouthern Apr 2016 #51
No Stuckinthebush Apr 2016 #64
Oh, I see. northernsouthern Apr 2016 #67
Never said any of that Stuckinthebush Apr 2016 #68
If you are serious northernsouthern Apr 2016 #69
I'm ok with the supers, yes Stuckinthebush Apr 2016 #71
I do think they are bought off. northernsouthern Apr 2016 #72
Well....no, they aren't "bought off" Stuckinthebush Apr 2016 #73
Sadly many of them. northernsouthern Apr 2016 #75
Wrong. they have to hit 2383 (I believe thats the correct number) Unicorn Apr 2016 #15
Nope. Once one of them reaches 2026 it is mathematically impossible Lucinda Apr 2016 #33
Which means at that point it goes to open convention. Unicorn Apr 2016 #34
No. It means that person will be the presumptive nominee. Lucinda Apr 2016 #35
No. Just first one this close. Unicorn Apr 2016 #36
The 2008 primary between Obama and Clinton was closer, much closer SFnomad Apr 2016 #37
Thanks for pointing that out. I don't rememer how the election 8 years ago went Unicorn Apr 2016 #39
This isn't close at all. Hillary has a huge lead, and with proportional delegates in every state Lucinda Apr 2016 #41
Incorrect TMontoya Apr 2016 #3
Oh? Did the DOJ and FBI end their investigations? CentralCoaster Apr 2016 #17
Yes it is TMontoya Apr 2016 #21
Since when? Yes, there are requirements. Unicorn Apr 2016 #20
.... MADem Apr 2016 #4
You are incorrect hack89 Apr 2016 #5
You are incorrect about 2008. Hillary conceded and still a third of the supers stuck with her. morningfog Apr 2016 #10
Hillary moved to stop the roll call and nominate Obama by acclamation. hack89 Apr 2016 #25
Probably. morningfog Apr 2016 #27
I know he will. He is a good Democrat. nt hack89 Apr 2016 #29
That was such a great moment at the 2008 Convention obamanut2012 Apr 2016 #58
She needs 175% of the remaining delegates, and Sanders needs just one delegate. Buzz Clik Apr 2016 #7
LOL livetohike Apr 2016 #13
the key number is 2026 pledged delegates, not 2383 geek tragedy Apr 2016 #8
Bullshit. 2,026 is NOT the number needed to win. That is dead wrong. morningfog Apr 2016 #11
okay, then when Clinton passes 2383 including her superdelegates geek tragedy Apr 2016 #19
2,383 is the number. She likely won't hit that until the supers vote at the convention. morningfog Apr 2016 #26
I get that you recognize the reality of the situation. geek tragedy Apr 2016 #30
Automatic delegates do not vote separately. LiberalFighter Apr 2016 #42
2383 is the number that includes pledged and super delegates. You know that. stopbush Apr 2016 #78
Exactly right. yardwork Apr 2016 #60
Quite screwy. jcgoldie Apr 2016 #9
Receiving enough earned delegates to win nomination outright will be difficult for her. pa28 Apr 2016 #12
Every delegate is earned Stuckinthebush Apr 2016 #18
Not quite, or not in the same ways. Orsino Apr 2016 #74
Sanders will not contest the nomination if he loses the voting. geek tragedy Apr 2016 #22
^^^^^^^^^^^ pdsimdars Apr 2016 #40
which means, by your definition, 2008 was an "open" convention onenote Apr 2016 #66
Not my definition. That is the definition and it doesn't happen very often. pa28 Apr 2016 #70
Hillary needs 67% of remaining pledged delegates to secure 2,383 through PDs alone. morningfog Apr 2016 #23
this is an accurate statement. nt geek tragedy Apr 2016 #24
thanks all boomer55 Apr 2016 #28
Hillary has 1930 delegates including everything. She needs around 459 more. Renew Deal Apr 2016 #31
I don't think that' exactly true. She needs those delegate to go from a plurality to a majority. HereSince1628 Apr 2016 #38
VIII. Procedural Rules of the 2016 Democratic National Convention LiberalFighter Apr 2016 #43
I think they can make a motion to suspend the rules HereSince1628 Apr 2016 #45
Highly unlikely to change that aspect. LiberalFighter Apr 2016 #46
Define who could be the delegates in "of the delegates voting" HereSince1628 Apr 2016 #47
She needs the majority of all delegates present at the the convention. LiberalFighter Apr 2016 #44
No you are not correct Demsrule86 Apr 2016 #48
If he truly loves this country he'll stay in boomer55 Apr 2016 #49
I vote for screwy math cemaphonic Apr 2016 #50
You are correct. TM99 Apr 2016 #52
Message auto-removed Name removed Apr 2016 #53
What does it matter? TM99 Apr 2016 #55
After PA and MD it will be less. nt Jitter65 Apr 2016 #54
No that is simply false Gothmog Apr 2016 #56
You left out a few words... Thor_MN Apr 2016 #57
Here's the easiest way to visualize the primary delegates... Sancho Apr 2016 #59
Your title is a bit misleading. Adrahil Apr 2016 #61
Not correct. Agschmid Apr 2016 #62
Message auto-removed Name removed Apr 2016 #63
No, you're not correct. You are applying #BernieMath. nt LexVegas Apr 2016 #65
Careful...basic math doesn't go over well here nt UMTerp01 Apr 2016 #76
Basic math shows that a majority of pledged deletes is 2026. The higher number that Bernie people pnwmom Apr 2016 #77
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