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Alekei_Firebird

(320 posts)
Sat Oct 13, 2012, 07:55 PM Oct 2012

If Obama has a 50 point lead with 19% of the Ohio early vote... Math geniuses welcome!

By how much does Romney have to win the remaining voters to pull out a win? At what point does it become all-but-mathematically-impossible for Romney to overcome such an early deficit?

Right now, Obama leads 76-24 with 19% of the voting already completed. If Romney maintains a 51-46 lead with the remaining 81% of the voters, what would the final numbers look like?

Here's my quick math:

About 5.6 million people voted in Ohio in 2008. Assuming that demographics and turnout are relatively similar, that would mean that about 1.1 million people have already voted. Of those 1.1 million, about 836 000 have voted for Obama and 264 000 have voted for Romney.

If Romney carries the remaining 4.5 million voters at a 51-46 advantage, then he'd have 2.3 million votes and Obama would have 2 million votes.

Final tally would be:

Obama: 2 836 000 (50.6%)
Romney: 2 564 000 (45.7%)

Just like in 2008, Obama wins Ohio by about 5%.

Is my math horribly flawed?

39 replies = new reply since forum marked as read
Highlight: NoneDon't highlight anything 5 newestHighlight 5 most recent replies
If Obama has a 50 point lead with 19% of the Ohio early vote... Math geniuses welcome! (Original Post) Alekei_Firebird Oct 2012 OP
I look at it this way... RedSpartan Oct 2012 #1
More than 56% percent. That's the math I got as well. writes3000 Oct 2012 #3
The only thing I don't get is SheilaT Oct 2012 #21
For the same reason that PPP's numbers don't add up to 100... RedSpartan Oct 2012 #22
Oh. SheilaT Oct 2012 #24
Let me try tarheelsunc Oct 2012 #2
Sounds about right. n/t Azathoth Oct 2012 #7
If Obama can take Ohio, HockeyMom Oct 2012 #4
My calculations exactly! cheezmaka Oct 2012 #34
No not horribly. :-) Sekhmets Daughter Oct 2012 #5
Another way of looking at it Applan Oct 2012 #6
Just as a note, these are extrapolations from polls, not actual vote results alcibiades_mystery Oct 2012 #8
What does this 19% represent? Is that of the expected vote? Can turnout affect it? dkf Oct 2012 #9
19% of Ohioans have already voted Azathoth Oct 2012 #10
Is that of all registered voters then? Seems kind of high. dkf Oct 2012 #11
All likely voters I assume n/t Azathoth Oct 2012 #13
Presumably LV, but yes - it seems high. FBaggins Oct 2012 #23
There were three OH polls. LisaL Oct 2012 #25
I'm not saying that they're lying. FBaggins Oct 2012 #29
Some might have voted via absentee ballots. LisaL Oct 2012 #37
Yep. FBaggins Oct 2012 #39
Let's not count our chickens just yet... regnaD kciN Oct 2012 #12
All three recent polls show Obama has a large lead among early voters. LisaL Oct 2012 #15
Uhhh.....let's see..... Doctor Jack Oct 2012 #14
Let's pretend that nobody has voted early, and O is leading 51 to 46 (PPP today). Looks good, no? Blaukraut Oct 2012 #16
A 50 Point Lead? So its a tie? Doctor Jack Oct 2012 #17
Not flawed brush Oct 2012 #18
wartch those absentee votes DonCoquixote Oct 2012 #19
Assume the 19% number is correct: bemildred Oct 2012 #20
Post removed Post removed Oct 2012 #26
Arithmetic. Historic NY Oct 2012 #27
It depends on what the 19% number represents. thevoiceofreason Oct 2012 #28
And further, if the 19% means of RV's thevoiceofreason Oct 2012 #30
Romney will need to win Ohio by double-digits Alekei_Firebird Oct 2012 #31
Depends on where in the state those numbers are from davidn3600 Oct 2012 #32
Good point. nt bemildred Oct 2012 #33
Yes. Cleveland especially. LisaL Oct 2012 #38
You need to figure 60% voter turnout, not 100% bushisanidiot Oct 2012 #35
While the turnout is not going to be a 100 % (it's never is) LisaL Oct 2012 #36

RedSpartan

(1,693 posts)
1. I look at it this way...
Sat Oct 13, 2012, 07:59 PM
Oct 2012

And we get to almost the exact same result...

Let's pretend there are 100 votes in Ohio.

19%, or 19 votes, have been cast, and Obama leads with them 76%-24%. So Obama has 14.44 votes and Romney has 4.56 votes.

81%, or 81 votes, have yet to be cast, and Romney leads with them 51%-45%. So Romney will have 41.31 votes and Obama will have 36.45 votes.

Add them up, and Obama has 50.89 votes and Romney has 45.87 votes -- essentially the same 51%-46% that PPP is reporting in total.

So unless I am mistaken (and I admit I likely am), it seems to me that if these numbers hold, Ohio is very, very, unlikely to go for Romney unless he can get the 81% of people who have not voted yet to go for him by closer to a 56%+ level. I can't see that happening.

 

SheilaT

(23,156 posts)
21. The only thing I don't get is
Sat Oct 13, 2012, 09:43 PM
Oct 2012

Last edited Sun Oct 14, 2012, 02:48 AM - Edit history (1)

why, out of 100 votes, your math only gives us 97 votes in the end?

edited for a typo.

 

SheilaT

(23,156 posts)
24. Oh.
Sat Oct 13, 2012, 10:14 PM
Oct 2012

But I would have thought doing the math the way it was done would have resulted in 100 votes. Never mind.

tarheelsunc

(2,117 posts)
2. Let me try
Sat Oct 13, 2012, 08:01 PM
Oct 2012

19*.76 = 14.44

50 - 14.44 = 35.56

35.56/81 = 43.9%

Assuming no third party candidate receives a vote and that 76%-24% is the correct margin as of now, Obama needs 44% of the remaining vote to win.

 

HockeyMom

(14,337 posts)
4. If Obama can take Ohio,
Sat Oct 13, 2012, 08:01 PM
Oct 2012

and more of the MidWest, then screw Florida which is, and especially now, is a very corrupt state.

cheezmaka

(737 posts)
34. My calculations exactly!
Sun Oct 14, 2012, 12:11 AM
Oct 2012

If Obama takes Ohio and also wins PA and WI, he will win even if he "lost" FL and every other battleground state.

Applan

(693 posts)
6. Another way of looking at it
Sat Oct 13, 2012, 08:05 PM
Oct 2012

If the 19% represents likely voters then Willard will need to carry the remainder of the votes at 56% to 44%

But if the 19% represents all eligible Ohio voters, and they get a 60% turnout as in 2008, then Romney would need to carry over 62% of the remaining votes.

Either way it's not looking too good for the rich git is it?

 

alcibiades_mystery

(36,437 posts)
8. Just as a note, these are extrapolations from polls, not actual vote results
Sat Oct 13, 2012, 08:07 PM
Oct 2012

Just saying, a word of caution is important here. Fight for every goddamn vote until the second the polls close.

Azathoth

(4,608 posts)
10. 19% of Ohioans have already voted
Sat Oct 13, 2012, 08:12 PM
Oct 2012

76% of those, or close to 15% of all Ohio voters, have already voted for Obama.

FBaggins

(26,737 posts)
23. Presumably LV, but yes - it seems high.
Sat Oct 13, 2012, 10:01 PM
Oct 2012

Every polling firm has their own minor tweaks on the likely voter screening... but I think it's fair to assume that anyone who says they already voted gets through the screen.

As for your reasonable assumption - I can only find reporting on 175k early votes so far. There are good reasons to think that this is low (some counties have not fully reported and some votes may be in the mail), but that's only 3% of 2008's total turnout. Additionally, early voting was just under 30% of the electorate (in Ohio) in 2008 - with the bulk of it coming just before election day.

So it does seem highly unlikely that 19% have actually voted already.

I don't know what that means for their sample. I'm unaware of any studies that compare responses to the "have you already voted?" question to actual voting. Maybe people claim that they've voted because they think it will make a political caller hang up (not all "pollsters" who call turn out to actually be pollsters). But that's just a preliminary guess.

LisaL

(44,973 posts)
25. There were three OH polls.
Sat Oct 13, 2012, 10:38 PM
Oct 2012

The earliest one said 10% already voted. The second poll said 18 % already voted. This current poll says 19 % already voted. Obama had a huge lead in all three polls for the early voters.

FBaggins

(26,737 posts)
29. I'm not saying that they're lying.
Sat Oct 13, 2012, 10:45 PM
Oct 2012

Just that the number is odd. There's an actual count of how many votes have been cast, and it doesn't seem to match these polls.

Also, I don't know how well you remember the 2010 election, but there were these kinds of projections based on polls and early voting figures. They were constantly used to show us that reality wasn't as bad as what the polling seemed to say it was.

I don't know whether it was faulty polling (nobody has a good track record of identifying people who have already voted), or faulty analysis... or just that Democrats vote early far more often even in losing races... but I'm much more comfortable talking about their headline number and just leaving off estimates of how far up we are in actual voting.

LisaL

(44,973 posts)
37. Some might have voted via absentee ballots.
Sun Oct 14, 2012, 01:01 AM
Oct 2012

Which could be in the mail thus not counted in the amount of those who already voted.

regnaD kciN

(26,044 posts)
12. Let's not count our chickens just yet...
Sat Oct 13, 2012, 08:19 PM
Oct 2012

Recall that all these figures are extrapolated from a poll, not official vote counts. It's taken from less than one-out-of-five respondents - if the PPP poll has a margin of error, I would think that the margin of error for a small subset of that poll would be considerably greater.

In other words, while it's reasonable to conclude that a significant bloc -- if still a minority -- of Ohio voters have already voted, and those who have show a significant tilt to Obama, starting to calculate detailed scenarios from those exact, down-to-one-hundredth-of-one percent figures is pretty much a fool's errand. Let's be happy that the PPP poll apparently shows us with a lead beyond the margin of error, and be happy with that.

Doctor Jack

(3,072 posts)
14. Uhhh.....let's see.....
Sat Oct 13, 2012, 08:37 PM
Oct 2012

...Ok, got it, 280%.....that can't be right. I never should have learned math from Paul Ryan!

Blaukraut

(5,693 posts)
16. Let's pretend that nobody has voted early, and O is leading 51 to 46 (PPP today). Looks good, no?
Sat Oct 13, 2012, 08:46 PM
Oct 2012

So I'm no math genius, but I doubt Romney can improve on the 51% to 46% advantage he has with those who haven't voted yet, unless Obama does something really stupid. Romney's momentum has stalled, and from the looks of it, he never had it in Ohio in the first place.

brush

(53,778 posts)
18. Not flawed
Sat Oct 13, 2012, 09:21 PM
Oct 2012

No it's not flawed if Romney were to get the 51-46 percent margin, but it's very highly unlikely if in the sample of actual voters that we have he's already behind 76 to 24. I'm thinking the final vote will more likely reflect the actual 76 to 24 numbers than 51-46 estimate of some poll.

DonCoquixote

(13,616 posts)
19. wartch those absentee votes
Sat Oct 13, 2012, 09:27 PM
Oct 2012

The ones the GOPloves because they are easily hackable...Florida always seems to get a wave of absentee voters that always vote GOP, surprise surprise.

bemildred

(90,061 posts)
20. Assume the 19% number is correct:
Sat Oct 13, 2012, 09:30 PM
Oct 2012

then 19% of 76% is ~.14 or 14% of the votes.

and

19% of 24% is ~5% of the votes.

So Obama has a lead of 9% of the votes.

iF the 19% number errs, the numbers would change in proportion, i.e. if it's really 25% complete, you would get 19% and 6%, so O's lead is 13%, bigger. If the true number is 10%, you'd get 7.6% and 2.4% and the advantage would be 5.2%, much smaller.

So it really depends on how accurate the 19% of the total vote estimate is.

Response to Alekei_Firebird (Original post)

thevoiceofreason

(3,440 posts)
28. It depends on what the 19% number represents.
Sat Oct 13, 2012, 10:45 PM
Oct 2012

If the 19% number means 19% of the expected turnout, then your math is correct.

If it means 19% of the registered voters, then we have to guesstimate what the turnout will be this year. The best data I can find is that the 2008 Ohio RV turnout was 65.5%. So assuming that is the case this year, 19/65.5 of expected voters, or 29%, have already voted. And the poll says President Obama leads that group by a 76-24 margin. That means that President Obama has 22% of the total expected turnout (29% X .76) already, and Rmoney has 7% (29% X .24).

So, for the remaining 71%, Rmoney needs to end up with a percentage of that amount which will give him 43.1% of the total, to give him 50.1% (7% + 43.1%) and win Ohio. Therefore, Rmoney would need 60.7% of the remaining 71% to end up with the 43.1% (60.7% X 71%) he needs to get over the top.

Net net: If the 19% having voted already means 19% of the RV's, and if turnout is similar to 2008, Rmoney needs 60.7% of the remaining votes. Good luck with that, brittle boy.

thevoiceofreason

(3,440 posts)
30. And further, if the 19% means of RV's
Sat Oct 13, 2012, 10:53 PM
Oct 2012

Then Rmoney's 51-45% advantage among those who have not yet voted is woefully inadequate (a phrase I am sure he has heard in many contexts in his life). That would mean that he is going to get 51% of the remaining 71%, or 36.21%. Add that to his current 7% gives him a total of 43.21% - a badass buttwhipping.

Alekei_Firebird

(320 posts)
31. Romney will need to win Ohio by double-digits
Sat Oct 13, 2012, 10:58 PM
Oct 2012

The numbers may be a little off b/c it's a poll, but multiple polls have given Obama at least a 40-point advantage with about 20% of Ohio's early votes.

Romney will likely have to win by an overall margin of double digits then.

God, that's gotta be disheartening for his campaign. I love it!

 

davidn3600

(6,342 posts)
32. Depends on where in the state those numbers are from
Sat Oct 13, 2012, 11:49 PM
Oct 2012

If most early voting is taking place in Cuyahoga or Franklin counties, that lead not surprising. I think in Cuyahoga county the Ds outnumber Rs by 2 to 1. So you would expect a large Obama lead in that county.

bushisanidiot

(8,064 posts)
35. You need to figure 60% voter turnout, not 100%
Sun Oct 14, 2012, 12:19 AM
Oct 2012

there was 60% voter turnout 4 years ago. this year it will likely be less. maybe %58.

LisaL

(44,973 posts)
36. While the turnout is not going to be a 100 % (it's never is)
Sun Oct 14, 2012, 12:59 AM
Oct 2012

I am not sure as to why it would be less.
I think in early voting OH is ahead of 2008 already.

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