As anyone who has studied probability theory knows, any sequence of numbers is as likely as any other. 1-2-3-4-5 is as likely to be the winning sequence as 5-9-18-22-30. Furthermore, the probability of winning two days in a row is perfectly easy to calculate. According to this web site:
http://www.mnlottery.com/numbers.htmlthe Northstar Cash game involves choosing 5 numbers between 1 and 31. So the probability of winning the jackpot on a given drawing is 1/169911 (i.e., about 1 in 170,000, as the article states; the details of the calculation are below). The probability of winning two days in a row is the square of that, or 1/28869747921, or roughly 1 in 29 billion. It's very small, but it's non-zero, which means it can happen. In comparison, the probability of winning a game where you choose 6 out of 49 numbers is 1/13983816, or roughly 1 in 14 million.
Choosing 5 numbers between 1 and 31, you're not allowed to repeat any numbers. You can't, for example, play 2-2-19-20-23. So there are 31 possibilities for the first number, 30 for the second, 29 for the third, 28 for the fourth, and 27 for the fifth. That's 31*30*29*28*27 = 20389320. But the order is not important, and there are 5*4*3*2*1 = 120 ways to order five numbers, so we divide by 120 and get 169911 possible combinations. The probability of winning two days in a row is the probability of winning the first day times the probability of winning the second day, so that's 1/169911*169911, or 1/28869747921. Keeping one of the numbers the same doesn't change this probability: once you've won the first day, any combination is once again as likely to win as any other.